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25x^2-250x+576=0
a = 25; b = -250; c = +576;
Δ = b2-4ac
Δ = -2502-4·25·576
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-250)-70}{2*25}=\frac{180}{50} =3+3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-250)+70}{2*25}=\frac{320}{50} =6+2/5 $
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